In this reworking of Arthur Barnett's example, values that exceed the original average 0.5 value are the counterparts of the values that
fall below it, e.g. 0.4 in the second iteration of the left skewed example becomes 0.625 in the second iteration of the right skewed example
so that the geometric mean of the two values, 0.4 and 0.625 is 0.5. Note that this makes a big difference in the symmetric example, where the
arithmetic mean shows higher and higher values with increasing variance but the geometric mean remains constant at 0.50.
In the variant of the symmetric example, this distribution would be considered skewed to the right since the upper values differ from
the median value by much more than the lower values do, however if one looks at the logs of the values there is symmetry. For example: